PullupDev/lib/ArduinoJson/extras/scripts/wandbox/JsonParserExample.cpp
tk 54adf4ad3f 【类 型】:chore
【主	题】:不从配置文件远端获取 ArduinoJson库 添加到根目录调用
【描	述】:
	[原因]:防止版本不同 造成bug
	[过程]:
	[影响]:
【结	束】

# 类型 包含:
# feat:新功能(feature)
# fix:修补bug
# docs:文档(documentation)
# style: 格式(不影响代码运行的变动)
# refactor:重构(即不是新增功能,也不是修改bug的代码变动)
# test:增加测试
# chore:构建过程或辅助工具的变动
2024-07-03 13:46:41 +08:00

60 lines
1.8 KiB
C++

// ArduinoJson - https://arduinojson.org
// Copyright © 2014-2022, Benoit BLANCHON
// MIT License
//
// This example shows how to deserialize a JSON document with ArduinoJson.
#include <iostream>
#include "ArduinoJson.h"
int main() {
// Allocate the JSON document
//
// Inside the brackets, 200 is the capacity of the memory pool in bytes.
// Don't forget to change this value to match your JSON document.
// Use https://arduinojson.org/v6/assistant to compute the capacity.
StaticJsonDocument<300> doc;
// StaticJsonDocument<N> allocates memory on the stack, it can be
// replaced by DynamicJsonDocument which allocates in the heap.
//
// DynamicJsonDocument doc(200);
// JSON input string.
//
// Using a char[], as shown here, enables the "zero-copy" mode. This mode uses
// the minimal amount of memory because the JsonDocument stores pointers to
// the input buffer.
// If you use another type of input, ArduinoJson must copy the strings from
// the input to the JsonDocument, so you need to increase the capacity of the
// JsonDocument.
char json[] =
"{\"sensor\":\"gps\",\"time\":1351824120,\"data\":[48.756080,2.302038]}";
// Deserialize the JSON document
DeserializationError error = deserializeJson(doc, json);
// Test if parsing succeeds.
if (error) {
std::cerr << "deserializeJson() failed: " << error.c_str() << std::endl;
return 1;
}
// Fetch values.
//
// Most of the time, you can rely on the implicit casts.
// In other case, you can do doc["time"].as<long>();
const char* sensor = doc["sensor"];
long time = doc["time"];
double latitude = doc["data"][0];
double longitude = doc["data"][1];
// Print values.
std::cout << sensor << std::endl;
std::cout << time << std::endl;
std::cout << latitude << std::endl;
std::cout << longitude << std::endl;
return 0;
}